a-2[b-4(c-x)]=2

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Solution for a-2[b-4(c-x)]=2 equation:


Simplifying
a + -2[b + -4(c + -1x)] = 2
a + -2[b + (c * -4 + -1x * -4)] = 2
a + -2[b + (-4c + 4x)] = 2
a + [b * -2 + -4c * -2 + 4x * -2] = 2
a + [-2b + 8c + -8x] = 2

Solving
a + -2b + 8c + -8x = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2b' to each side of the equation.
a + -2b + 8c + 2b + -8x = 2 + 2b

Reorder the terms:
a + -2b + 2b + 8c + -8x = 2 + 2b

Combine like terms: -2b + 2b = 0
a + 0 + 8c + -8x = 2 + 2b
a + 8c + -8x = 2 + 2b

Add '-8c' to each side of the equation.
a + 8c + -8c + -8x = 2 + 2b + -8c

Combine like terms: 8c + -8c = 0
a + 0 + -8x = 2 + 2b + -8c
a + -8x = 2 + 2b + -8c

Add '8x' to each side of the equation.
a + -8x + 8x = 2 + 2b + -8c + 8x

Combine like terms: -8x + 8x = 0
a + 0 = 2 + 2b + -8c + 8x
a = 2 + 2b + -8c + 8x

Simplifying
a = 2 + 2b + -8c + 8x

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